Hope that you can see the question clearly but here is the question once more 🙂
The contents of the flash drive appear to be password protected. On the back of the flash drive, you see the hexadecimal number 0x95f48ed9 scribbled in ink. The password prompt, however, only accepts decimal numbers. What number should you enter? (Press the Hint button for advice on solving the challenge)
You could try asking Google or Wolfram Alpha
I really think that everyone was able to get through this question 😀 Let’s go with the hints first
To me googling did not work 😦
But wolframalpha.com did the job as in the hint, but I have never heard of this and I needed a account to get get the result, so there is no other option than creating one 🙂
After entering our number in hex (hexadecimal). If you have no idea of what I am speaking about you better visit this wiki page and read more about the Number Representation 🙂 Remember here that our goal is not getting the flag by doing something that even you don’t understand, CTF is an excellent platform to learn things.
http://en.wikipedia.org/wiki/Hexadecimal
So we need to convert the given hex value to decimal, the wolfram works good but I think that we can do it in a better manner 🙂 in python with a single line of code 🙂
here is the code
#!/usr/bin/env python print int(0x95f48ed9)
#!/usr/bin/env python print 0x95f48ed9
or we could do the same on the python interpreter by just typing the number or by using the int function before it.
>>> 0x95f48ed9 2515832537 >>> int(0x95f48ed9) 2515832537 >>>
So we got the password in different manner which is nothing but decimal value of the 0x95f48ed9 so our flag is
2515832537
Happy hacking, 😀 hoping that I will be able to write all the writeup’s 😉
picoCTF 